Q: What are the first 4 terms of the sequence which has the nth term formula?

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10

2,1,0 is th sequence of its terms

The first four terms are 3 9 27 81 and 729 is the 6th term.

Assuming each term is 3 MORE than the previous term t(n) = -13 + 3*n where n = 1, 2, 3, ...

4,8,12,16,20

Depends on the sequence. There may be a formula for the Nth term in which case it is easy. Or the value may depend on some combination of previous terms (as in the Fibbonaci series).

nth term is 8 - n. an = 8 - n, so the sequence is {7, 6, 5, 4, 3, 2,...} (this is a decreasing sequence since the successor term is smaller than the nth term). So, the sum of first six terms of the sequence is 27.

10

91=3n

In this case, 22 would have the value of 11.

I try to be psychic, but fail miserably. If you could give me a clue, like the first few terms of the sequence, I could have a go at giving you the 77th term.

If the Fibonacci sequence is denoted by F(n), where n is the first term in the sequence then the following equation obtains for n = 0.

5

1, 16, 81, 256 14641 is the 11th term.

6

If the formula for additional terms was the summation of the term before it, the nth term of the series would be the sum of all terms prior. In other words it would be the summation of a through n minus 1.

It is the description of a rule which describes how the terms of a sequence are defined in terms of their position in the sequence.

If the nth term is n*7 then the first 5 terms are 7, 14, 21, 28, 35.

you must find the pattern of the sequence in order to find the next 50 terms using that pattern and the first part of the sequence given

The sum of the terms in a sequence is called a series. Sequence is a function whose domain is the natural numbers. So f(1)= first entry in the sequence, and f(2) is the next.... f(n) is the nth term. We usually don't write sequences that way. Instead of f(1) we write, a1 to refer to the first term. The function tells us the rule we use to find the terms of the sequence. So for example, f says take n and square it. Then the first 3 terms of the sequence are 1, 4 and 9 and the first 3 terms of the series are 1, 5 and 14

Formula for nth termTn = a + (4n - 1) {where a is the first term and n is natural number}

37

5, 11, 17, 23, 29

No, they do not. If the first term is negative, they always decrease.

t(1) = 1t(2) = 1t(n) = t(n-2) + t(n-1) for n = 3, 4, 5, ...that is, the first and second terms are 1. After that, each term is the sum of the previous two terms.

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